Bushnell 4200 6-24 X Mil Dot Reticle Question

R

rollinghills

New member
What diameter are the Mil Dots in the 6-24X at 12X magnification? The diagram on the Bushnell website shows that Mil Dots are 1/2 Mil in Diameter when the Dot centers are separated by 1 Mil. Those would be pretty coarse Dots which would subtend 1.8" at 100 yards. Is the website diagram correct? 1/4 Mil Diameter Dots would seem to make more sense for the standard 1 Mil separation of Mil Dot centers. I have to buy this scope through mail order and will not have a chance to examine it before I buy it, so your feedback is appreciated. Thanks.

rollinghills
 
if the reticle in in the second focal plane, the mils are accurate at one certain power, most are 10x, then one mil is 3.68 moa per 100 yds of range.
1 mil= 3.68 (moa) x1.047= 3.85296" per 100 yds
RR
 
Rollinghills-- if they're too big at 12X then u could always recalibrate the reticle subtensions for a higher magnification-- if they're 1.8 inch per hundred yds. @ 12X they'll subtend about 1/2 that measurement @ 24X or .9". Then of course the "mil" subtension would be 1/2 x 3.6 or 1.8 as well.
 
Hi Rollinghills,

I have that scope and there is a mis-understanding there. The dots are approx. 3/4" moa on 12x, 3/8" on 24x. The dot size is fine on higher varmint power.


All mil dots........."dots" are type .2" or .25" of a mil (3.6") in size.
Go back a couple pages here to a topic called

VARMINTS / MIL DOT

For much information. Also I used the bushnell 6-24x40 as an example of a ideal mil dot scope for varmints.
 
Thanks for the welcome and all the information. It sounds like the Bushnell website Mil Dot Diagram is dimensioned incorrectly. I'll get one on order this weekend.

rollinghills
 
Of course Bill--no way the dot takes up .5 mil subtension. Shoulda thought about that a second longer, i guess. That'd be just a lttle on the BIG side. But as u can see Rollinghills, the subtension changes proportionally with magnification change-- actually inversely proportional (assuming the power ring is calibrated correctly)-- .75" at 12X, or .375"@ 24X, and if that's the case the inversely proportional formula would work then to calibrate any size subtension u want, since the power ring is probably calibrated correctly.
 


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