Bullet revolutions per 100 yards

Originally Posted By: CatShooterOriginally Posted By: SmokelessOriginally Posted By: CatShooterOriginally Posted By: Jerry TracyI'm assuming that the bullet will lost its spin rate just as it looses its velocity?

It does not - it looses forwards velocity much faster than the spin rate - so in 100 yds, it spins more than the formula suggests.


.

This ratio is why, if properly stabilized at the muzzle, a bullet will become more stable down range gyroscopically. Sometimes with very long bullets that require a lot of stabilization, accuracy at 200yds is better than it is at 100yds.


Not true, and not related at all.

1 - If a bullet starts out unstable, it will never be stable. Pesky laws of physics.

2 - A bullet that is not accurate at 100 yards, cannot be accurate at a further distance - to do so, it would presuppose that the bullet was intelligent. First, it would know that it was off track at 100 yards. Then it would know which direction to turn and correct (in a world that is spinning at 250,000+ rpm), could intelligently change it's direction to correct, and then know when it was back on track, and do a second path correction to go straight ahead.

It is not physically possible.

When your groups are smaller down range (in size OR m.o.a.) you have a parallax problem.




Is true. I will agree that it is not related to the original post.

I was trying to go further to include Bullet precession, coning, yaw, stability factor[Sg], dynamic stability, and static stability. They all come to play in bullet rpm.

When I have more time I will post a new thread for the subject. It will be a good one.
 
Originally Posted By: Ridgeline17Check this site out if I'm understanding what everybody is talking about here. www.nennstiel-ruprecht.de/bullfly

A lot of the stuff on that site is BS... and it violates basic laws of physics.


All of this stuff MUST conform to the laws of physics - if it doesn't, no matter how impressive and complex the math formulas are and how cute the diagrams and graphs are - it is worthless.

If these guys could prove what they say, then they are in line for a Nobel Prize in physics - which is worth USD $1,300,000 and you get a bigassed university named after you.

I used to write this kind of crap when I was at Columbia University, and if you make it convoluted enough, you can baffle a peer review committee with ease.
 
Nevermind then the newbie is shuttin up.
blushing.gif
Ill just go stand in the corner now.
 
Last edited:
Took me about 1 min 42 sec to read everyting on that page, I learned nothing other than blue letters are hard to read. LOL
 
Originally Posted By: Ridgeline17Nevermind then the newbie is shuttin up.
blushing.gif
Ill just go stand in the corner now.

It's good to try and learn, but as said many a time before, the interweb is a crappy place to quote.
 
Read in a couple of other places too. To what they are sayin, I guess the best way to describe is like an arrow when its launched out of a bow. The only thing that puzzles me is that according to what I'm reading the bullet is always pulled to the right? I'll let somebody explain all of this. Feel like I've been in a physics class again.
scared.gif
 
Regarding the "more stable" comments:

There's a misconception that "stable" is the same as "accurate". I'd very easily believe that a bullet can become more "stable" in flight, but I do agree that a bullet cannot become "more accurate" in flight. Accuracy is really about the line traced by the center of mass of the bullet, so a bullet can be flying straight towards the target but still be wobbling.

You see this in arrows, or even in football spirals. How many times have we watched that dramatic "ball in flight" slow motion where the ball leaves the QB's hand like a lame duck, then tightens up into a nice spiral in flight? That's what spin stabilization does, that's why we shoot rifles.

To the topic at hand, the angular velocity will remain essentially constant. Yes, the spin DOES slow because it's resisted by slight wind drag. HOWEVER, (about to get all "fluid dynamical" on ya) because the bullet is moving FASTER perpendicular to the direction of the rotation, the boundary layer is sloughed off the rear of the bullet, presenting essentially no resistance to the spin.

So a .223rem pushed out at 3400fps from a 1:9" will maintain a ~4533rps spin for a long dang ways.

Easiest way, in my opinion, to calculate how many times a bullet rolled over in flight is to multiply: time of flight for a given range times barrel twist rate times muzzle velocity = revolutions over that range.

Just for fun, a .223rem from an 1:8.5" will have ALMOST the same rotational face velocity in inches per second as it will lateral velocity at the muzzle in feet per second... 3400fps gives 3363 inches per second, 3200fps = 3165"/s, 3000fps = 2967"/s. Basically has a 1/12 angle in the flow field across/around the bullet.
 
Cat, not to be a stickler, but what about this article is bad science? I have discussed this and read about it for a while, and there seems to be some common agreement out there. Not to say that common agreement is all powerful (there are nuts that tell people that humans somehow are ending the ice age of the Pleiocene (sp?) but I know that such global warming crap is rubbish). I am just curious to know your take on all this so that I am better informed than I am of the detractors from the theory that bullet accuracy group size are possible in theory to remain the same over an extended distance, or even similar to the point that the MOA calculation (as a percentage of spread) actually decreases. I am serious, I really want to know what you mean that it is false (implied) or based in bad science (stated).
 
Originally Posted By: Jabey9210if the bullet is spinning 1 rev per 9 inches it will continue to spin once every 9 inches until it hits the target or the ground yes the revolution slows down but so does the velocity even though it takes the bullet longer in time to rotate it also takes it longer in time to travel the 9 inches and will continue to rotate once every nine inches.

This is absolutely NOT true. The rotational speed (angular velocity) and the lateral speed of the bullet are independent. For this to be true, the bullet would have to slow down in air speed AND angular velocity at the same rate of decline, which DOES NOT HAPPEN.

Newton's law for the conservation of momentum is applicable here, in two essentially independent cases (not 100% independent because as the bullet slows, the boundary layer around the bullet is sloughed more slowly, causing a greater resistance to rotation, but that's an entirely different ball of wax...). The bullet is fighting through the air, causing it to slow, in the 3000fps ballpark. The rotation of the bullet is fighting a MUCH lower drag force, and therefore it won't be retarded nearly as quickly as the bullets air speed.

The 1:9" is ONLY relevant at the muzzle. The bullet WILL continue to spin at the same ANGULAR VELOCITY, as in RPM's, with some retardation factored in over the range, but it will NOT maintain 1 turn per 9" of bullet flight. As soon as a bullet leaves the barrel, it will actually start making MORE turns per linear foot, because it will continue spinning at approximately the same rpm's, but will travel farther "per minute" than it did at the muzzle.
 
Varminterror, how would a buller increase in speed AFTER leaving the muzzle???? I think you missed something there, as there is no longer present propulsion once the gasses behind the bullet are no longer pressing against it's base! It WILL slow continually until it strikes something at which point it will slow RADICALLY until it stops altogether.
 
Ok Cat Ill leave it alone. I respect your knowledge and I don't want to stir anything up. But some of that is some pretty interesting stuff. Anyhow your my teacher I will listen.
 
Originally Posted By: BubbaChickenCat, not to be a stickler, but what about this article is bad science? I have discussed this and read about it for a while, and there seems to be some common agreement out there. Not to say that common agreement is all powerful (there are nuts that tell people that humans somehow are ending the ice age of the Pleiocene (sp?) but I know that such global warming crap is rubbish). I am just curious to know your take on all this so that I am better informed than I am of the detractors from the theory that bullet accuracy group size are possible in theory to remain the same over an extended distance, or even similar to the point that the MOA calculation (as a percentage of spread) actually decreases. I am serious, I really want to know what you mean that it is false (implied) or based in bad science (stated).

You can be a stickler, I don't mind - but it is such a long "type" - I need a secretary!
frown.gif
frown.gif
frown.gif


"I finally had to re-read the section in McCoy's book "Modern External Ballistics"[1] to get to confirm this assertion that it is possible for a group size in terms of MOA to get smaller at longer ranges for some projectiles."

No one has ever documented that a rifle can shoot smaller groups at a longer range. Such a documentation would require a benchrest grade rifle to be mounted in a machine-rest, on a concrete base, so NO movement could occur, not eve 1/10000".

Several bullet companies use such rigs to test the production bullets for group before releasing the lot number - none of these companies have ever seen a bullet that makes groups smaller at long range (in group size or MOA). If you ask them about it, they just giggle.


"This is unquestionably true. I have observed this myself at the range, and Chapter 11, Section 4 discusses this clearly. They even do an analysis for a 168 grain SMK, 0.308 bullet. Here is a quick summary:

If the bullet yaws coming out of the muzzle, you can observe three distinct errors or deviations from the "perfect" trajectory. The first is "Aerodynamic Jump", which is a complicated way of saying that the bullet will go in the direction of the tip as it yaws at the exact moment of exit. This causes the majority of the deviation from the "perfect" path that we see. Just what causes the bullet to yaw at that exact moment is what I am most interested in studying, and is the essence of the research into the Acoustic Shock Wave theories."

"Aerodynamic Jump", which is a complicated way of saying that the bullet will go in the direction of the tip as it yaws at the exact moment of exit.

This is pure BS - the bullet comes out of the muzzle in a straight line - it is impossible for it to exit at an angle, because that would mean that (for a 30 cal) the .308" diameter body would have to be canted in a .308" bore (a physical impossibility).

If the bullet "yaws" after the exit, then it is traveling in a new (non-coaxial) direction, and the center of mass determines the direction - if the center of mass if going in a new direction, then the bullet is now going in a new direction, and there is no force to bring it back, because the bullet doesn't know where "back" is.

There have been millions of high speed photos of bullets leaving the muzzle, and none of them show a bullet going off in a new direction - this is pure speculation on the part of the writer.

The second error is a "Epicyclic Swerve", which is a fancy way of saying that the bullet chases its tip as it wobbles (precesses, like a top) as it flies along. This causes aerodynamic forces to make the bullet travel in a helical path around the now disturbed path (remember the Jump error!). For most small arms bullets, the damping forces on this wobble are very small, and in the case of the 168 grain SMK, are actually positive, meaning that the helix INCREASES in size as it goes down range. In other words, it doesn't go to sleep, it gets more awake! So, if the Swerve component is on the order of 0.25", it stays at this level, or gets slightly bigger as the bullet goes down range. If you keep the Jump error small then this is what you will observe, a 0.5" group at 100, and 0.5" at 200, etc. Here is where you can see that the MOA can actually decrease at longer ranges. The group size never decreases, but the dispersion in terms of MOA does. A subtle but important difference.

"Epicyclic Swerve" is pure fantasy - if the bullet is disturbed after leaving the muzzle, then there are several "givens" that apply to everything in the universe that moves.

1 - When an item moves through space, the center of mass (the center of gravity for you old guys) travels along the "line" of movement - any other projections, like points or appendages can flail around this axis, but the path is defined by the motion of the center of mass.

2 - If a mass is in motion, and the direction is disturbed, and the mass takes a new direction,, the new direction now becomes "it's direction" without any "memory" of the old direction. This means that there is no "memory" of past directions, so the mass cannot find it's way back, since it doesn't know where "back" is.

3 - If a spinning object encounters a force that causes pressure to be applied to disturb the axis of spin, the object will move 90° from the direction of the force - id est, if you push the nose of a bullet down, or lift it's tail, it will turn 90° left, NOT nose down.

This is not my opinion, this is the law of precession and yo cannot change the laws of of physics - no matter who you are!

When the force is removed, the bullet will NOT return to it's original attitude. The new (90° left direction) is now the new "true" direction.

Following is a very important video taken at a research center - the gyroscope was placed in a box at the top of an 85 foot tower - along with a video camera. When the box is dropped, the camera travels with it.
When the box is dropped, the gyroscope is in "0" gravity and you can see how it and you can see how a spinning object behaves "in air".



Note in the first video, the gyroscope is vertical and stable, and when the box is released, the gyroscope stays pointing in the same direction (the bullet is shot and flying true).

In the second part of the video, the gyroscope is off axis to the force (gravity) and is showing the effect of procession. Note that when the box is released, and the support is removed (the force causing precession) the gyroscope STOPS and stays pointing in the last direction is was, when under the force of precession.

There are two important things to note here - IF, a bullet is launched, and for whatever reason, starting to process or yaw, 1 - since the bullet keps on moving through the air, the force of the air on one side of the bullet nose will continue for the complete flight of the bullet, so it will NEVER stop processing - in fact, the processing will get worse as the bullet travels down range, and I am sure that some of you have seen bulet holes that are sideways in down range targets. And @, IF it was possible to remove the wind force on the aff axis nose of a precessing bullet, the second part of the vider shows that the bullet will stop it's yaw and then keep pointing OFF AXIS nd never return to the axis of the bore (whew, I need a sandwich
wink.gif
)

"The third error aptly called "Drift", is a steady (and increasing with range) drift of the flight path to the left or the right as a result of gyroscopic precession from the aerodynamic force applied as the bullet drops. Even though the bullet is moving forward at over 2000 feet per second, it drops (accelerates downward) in exactly the same manner as if it were dropped off the loading bench. As the bullet's downward velocity component increases, a small aerodynamic force is applied under the tip of the bullet, which tries to push the tip up. Since the bullet is spinning like a gyroscope (right hand spin for this example), this upward twist force or torque will result in the nose of the bullet yawing to the right. This yaw is called the "yaw of repose". This yaw in turn causes the bullet to steer a bit to the right (following the nose). The longer the bullet is in the air, the more the downward velocity increases, which causes a continually increasing the yaw of repose, which makes the bullet drift to the right even faster. For our class of projectiles this drift to the right is quite small, on the order of 15 inches for a 0.308 caliber bullet at 1000 yards. It is also fairly predictable, and can be seen as a predictable bias to our long range POI.

Also, BS... "drift" is caused because bullets do not travel nose down - they fly the whole length of their travel, pointing at the same angle that they were launched - so if you are shooting at 1000 yds, and the barrel is pointing up by 5°, then down range, it may be falling at 30° down, but it will be pointing 5° up - in other words, it will be traveling sideways.

When traveling sideways, the air under it will come in contact with the "under belly" of the bullet, and the rotation will cause air to be pulled from the right side over to the left side (looking from the rear) - (it is the same as the forces that cause curve balls in baseball) - the result is that the bullet is pulled to the right - not much at first, but an increasing amount as it travels down range - some "theorists" say 20" to 40" at 1,000 yds, but these green children have never shot at 1,000 yards. The real amount is a few inches... most of the time, an error that is lost in the "noise" of shooting errors.

"So, we are left with an initial Jump that does most of the damage, and a helical Swerve component that comes along with an off-angle departure. The helix stays about the same as the bullet travels downrange, so the Jump is what we see as the major factor for group size dispersion. If we get the Jump down (excellent bullet balance, neck/case/bullet/throat alignment, excellent barrel, excellent crown), then we start to see the helical component. Some say that the "bullet goes to sleep" at longer ranges. It is actually that the Jump error accumulates as range increases, and swamps out the helical Swerve. The Swerve error is still there, you just can't see it as it is dominated by the initial Jump error.

To paraphrase, "So it is true, that this article is a P.O.S. and loaded with...

BullPoo-forums.jpg
CopyofBSMeter.gif



.

Pardon any typos, I need a nap!


.
..
 
Originally Posted By: CatShooterOriginally Posted By: Jabey9210

"If people are more accurate at 200 yards than they are at 100 yards they should try to turn there magnification down at 100 yards if they have a 20 power scope turned all the way up at 200 yards if they shoot at 100 yards with it turned down to 10 power they will find their groups will shrink up. I don't know how to explain it in words but try it it really does work "



I'll "try", but I think it is an uphill battle.

If your scope changes group size at different powers and different ranges, then you might be a redneck - or you are suffering from the deadly curse of... Parallax.

Go here and read this (twice).

http://www.snipercountry.com/Articles/Parallax.asp

Then come back and ask questions (if you still have them).

Parallax causes bigger problems (and bigger groups) as power is increased. Most guys think they have parallax under control - they don't!


.


I'm not saying it's because of the scope that groups shrink I'm saying it has to do with the way you are seeing the target and aiming at it maybe it's a parallax thing I don't know all I know is my buddy is a gunsmith and builds a lot of long range rigs and we have found that when he builds some people guns they tell him that their groups are smaller at 200 yrds than they are at 100 yrds. I read an article a long time ago I have no idea where but it stated to turn your scope down half the power that you normally have it on while shooting 200 yrds when shooting 100yrds and because you are essentially making the same shot because the target is the same size in your scope your groups will shrink at the closer distance. This is what I read and we've tried it and it truely does work. Don't knock til you've tried it.
 
Originally Posted By: BubbaChickenVarminterror, how would a buller increase in speed AFTER leaving the muzzle????

You are absolutely mistaking what I said

Originally Posted By: VarminterrorThe 1:9" is ONLY relevant at the muzzle. The bullet WILL continue to spin at the same ANGULAR VELOCITY, as in RPM's, with some retardation factored in over the range, but it will NOT maintain 1 turn per 9" of bullet flight. As soon as a bullet leaves the barrel, it will actually start making MORE turns per linear foot, because it will continue spinning at approximately the same rpm's, but will travel farther "per minute" than it did at the muzzle.

I did not say it would increase speed after leaving the muzzle, nor did I say that a bullet will increase in rotational speed (angular velocity). A bullet will, however, make more revolutions per foot of travel at 100yrds than it did at the muzzle. It's a simple fact that the bullets rotation slows down much less than its airspeed, so it WILL spin revolutions per linear foot down range than it did at the muzzle.

What you are not understanding is that the "period of measure" is actually getting longer...

For example:

A .223rem at 3400fps out of a 1:9" barrel has an initial rotation of 4533 1/3 revolutions per second, which for our purpose, I won't make assumptions for how much the rotation slows, but it's fairly accurate to say that it doesn't slow any appreciable amount. At 3400fps, that first foot only takes 0.000294sec, and the bullet will make approximately 1.333 rotations in that first foot (corresponding to the 1:9" barrel twist).

HOWEVER, at 100yrds, that bullet will have slowed down to about 2955fps (at least my 50grner's are), so now traveling one foot takes 0.000338sec, so from 300-301ft, that bullet will turn 1.53 rotations in one foot.

Similarly, at 1000yrds, that bullet will have slowed down to 890fps, meaning it takes the bullet 0.00112sec to cover 1 foot, meaning it will roll over 5.1 times in 1 foot at 1000yrds.

As the bullet slows down, it will make MORE AND MORE rotations per foot. Yes, it is very easy to misunderstand this as its spin "speeding up", but no, that is NOT what I said.

The rotations per FOOT is not constant, like some of the other posters have mistakenly claimed.

Originally Posted By: Jabey9210if the bullet is spinning 1 rev per 9 inches it will continue to spin once every 9 inches until it hits the target or the ground yes the revolution slows down but so does the velocity even though it takes the bullet longer in time to rotate it also takes it longer in time to travel the 9 inches and will continue to rotate once every nine inches.
 
Back
Top